0=(10x)-(10x^2)/2-50

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Solution for 0=(10x)-(10x^2)/2-50 equation:



0=(10x)-(10x^2)/2-50
We move all terms to the left:
0-((10x)-(10x^2)/2-50)=0
We add all the numbers together, and all the variables
-(10x-10x^2/2-50)=0
We get rid of parentheses
10x^2/2-10x+50=0
We multiply all the terms by the denominator
10x^2-10x*2+50*2=0
We add all the numbers together, and all the variables
10x^2-10x*2+100=0
Wy multiply elements
10x^2-20x+100=0
a = 10; b = -20; c = +100;
Δ = b2-4ac
Δ = -202-4·10·100
Δ = -3600
Delta is less than zero, so there is no solution for the equation

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